[VOL-5486] Fix deprecated versions
Change-Id: I3e03ea246020547ae75fa92ce8cf5cbba7e8f3bb
Signed-off-by: Abhay Kumar <abhay.kumar@radisys.com>
diff --git a/vendor/github.com/klauspost/compress/flate/huffman_code.go b/vendor/github.com/klauspost/compress/flate/huffman_code.go
new file mode 100644
index 0000000..be7b58b
--- /dev/null
+++ b/vendor/github.com/klauspost/compress/flate/huffman_code.go
@@ -0,0 +1,417 @@
+// Copyright 2009 The Go Authors. All rights reserved.
+// Use of this source code is governed by a BSD-style
+// license that can be found in the LICENSE file.
+
+package flate
+
+import (
+ "math"
+ "math/bits"
+)
+
+const (
+ maxBitsLimit = 16
+ // number of valid literals
+ literalCount = 286
+)
+
+// hcode is a huffman code with a bit code and bit length.
+type hcode uint32
+
+func (h hcode) len() uint8 {
+ return uint8(h)
+}
+
+func (h hcode) code64() uint64 {
+ return uint64(h >> 8)
+}
+
+func (h hcode) zero() bool {
+ return h == 0
+}
+
+type huffmanEncoder struct {
+ codes []hcode
+ bitCount [17]int32
+
+ // Allocate a reusable buffer with the longest possible frequency table.
+ // Possible lengths are codegenCodeCount, offsetCodeCount and literalCount.
+ // The largest of these is literalCount, so we allocate for that case.
+ freqcache [literalCount + 1]literalNode
+}
+
+type literalNode struct {
+ literal uint16
+ freq uint16
+}
+
+// A levelInfo describes the state of the constructed tree for a given depth.
+type levelInfo struct {
+ // Our level. for better printing
+ level int32
+
+ // The frequency of the last node at this level
+ lastFreq int32
+
+ // The frequency of the next character to add to this level
+ nextCharFreq int32
+
+ // The frequency of the next pair (from level below) to add to this level.
+ // Only valid if the "needed" value of the next lower level is 0.
+ nextPairFreq int32
+
+ // The number of chains remaining to generate for this level before moving
+ // up to the next level
+ needed int32
+}
+
+// set sets the code and length of an hcode.
+func (h *hcode) set(code uint16, length uint8) {
+ *h = hcode(length) | (hcode(code) << 8)
+}
+
+func newhcode(code uint16, length uint8) hcode {
+ return hcode(length) | (hcode(code) << 8)
+}
+
+func reverseBits(number uint16, bitLength byte) uint16 {
+ return bits.Reverse16(number << ((16 - bitLength) & 15))
+}
+
+func maxNode() literalNode { return literalNode{math.MaxUint16, math.MaxUint16} }
+
+func newHuffmanEncoder(size int) *huffmanEncoder {
+ // Make capacity to next power of two.
+ c := uint(bits.Len32(uint32(size - 1)))
+ return &huffmanEncoder{codes: make([]hcode, size, 1<<c)}
+}
+
+// Generates a HuffmanCode corresponding to the fixed literal table
+func generateFixedLiteralEncoding() *huffmanEncoder {
+ h := newHuffmanEncoder(literalCount)
+ codes := h.codes
+ var ch uint16
+ for ch = 0; ch < literalCount; ch++ {
+ var bits uint16
+ var size uint8
+ switch {
+ case ch < 144:
+ // size 8, 000110000 .. 10111111
+ bits = ch + 48
+ size = 8
+ case ch < 256:
+ // size 9, 110010000 .. 111111111
+ bits = ch + 400 - 144
+ size = 9
+ case ch < 280:
+ // size 7, 0000000 .. 0010111
+ bits = ch - 256
+ size = 7
+ default:
+ // size 8, 11000000 .. 11000111
+ bits = ch + 192 - 280
+ size = 8
+ }
+ codes[ch] = newhcode(reverseBits(bits, size), size)
+ }
+ return h
+}
+
+func generateFixedOffsetEncoding() *huffmanEncoder {
+ h := newHuffmanEncoder(30)
+ codes := h.codes
+ for ch := range codes {
+ codes[ch] = newhcode(reverseBits(uint16(ch), 5), 5)
+ }
+ return h
+}
+
+var fixedLiteralEncoding = generateFixedLiteralEncoding()
+var fixedOffsetEncoding = generateFixedOffsetEncoding()
+
+func (h *huffmanEncoder) bitLength(freq []uint16) int {
+ var total int
+ for i, f := range freq {
+ if f != 0 {
+ total += int(f) * int(h.codes[i].len())
+ }
+ }
+ return total
+}
+
+func (h *huffmanEncoder) bitLengthRaw(b []byte) int {
+ var total int
+ for _, f := range b {
+ total += int(h.codes[f].len())
+ }
+ return total
+}
+
+// canReuseBits returns the number of bits or math.MaxInt32 if the encoder cannot be reused.
+func (h *huffmanEncoder) canReuseBits(freq []uint16) int {
+ var total int
+ for i, f := range freq {
+ if f != 0 {
+ code := h.codes[i]
+ if code.zero() {
+ return math.MaxInt32
+ }
+ total += int(f) * int(code.len())
+ }
+ }
+ return total
+}
+
+// Return the number of literals assigned to each bit size in the Huffman encoding
+//
+// This method is only called when list.length >= 3
+// The cases of 0, 1, and 2 literals are handled by special case code.
+//
+// list An array of the literals with non-zero frequencies
+//
+// and their associated frequencies. The array is in order of increasing
+// frequency, and has as its last element a special element with frequency
+// MaxInt32
+//
+// maxBits The maximum number of bits that should be used to encode any literal.
+//
+// Must be less than 16.
+//
+// return An integer array in which array[i] indicates the number of literals
+//
+// that should be encoded in i bits.
+func (h *huffmanEncoder) bitCounts(list []literalNode, maxBits int32) []int32 {
+ if maxBits >= maxBitsLimit {
+ panic("flate: maxBits too large")
+ }
+ n := int32(len(list))
+ list = list[0 : n+1]
+ list[n] = maxNode()
+
+ // The tree can't have greater depth than n - 1, no matter what. This
+ // saves a little bit of work in some small cases
+ if maxBits > n-1 {
+ maxBits = n - 1
+ }
+
+ // Create information about each of the levels.
+ // A bogus "Level 0" whose sole purpose is so that
+ // level1.prev.needed==0. This makes level1.nextPairFreq
+ // be a legitimate value that never gets chosen.
+ var levels [maxBitsLimit]levelInfo
+ // leafCounts[i] counts the number of literals at the left
+ // of ancestors of the rightmost node at level i.
+ // leafCounts[i][j] is the number of literals at the left
+ // of the level j ancestor.
+ var leafCounts [maxBitsLimit][maxBitsLimit]int32
+
+ // Descending to only have 1 bounds check.
+ l2f := int32(list[2].freq)
+ l1f := int32(list[1].freq)
+ l0f := int32(list[0].freq) + int32(list[1].freq)
+
+ for level := int32(1); level <= maxBits; level++ {
+ // For every level, the first two items are the first two characters.
+ // We initialize the levels as if we had already figured this out.
+ levels[level] = levelInfo{
+ level: level,
+ lastFreq: l1f,
+ nextCharFreq: l2f,
+ nextPairFreq: l0f,
+ }
+ leafCounts[level][level] = 2
+ if level == 1 {
+ levels[level].nextPairFreq = math.MaxInt32
+ }
+ }
+
+ // We need a total of 2*n - 2 items at top level and have already generated 2.
+ levels[maxBits].needed = 2*n - 4
+
+ level := uint32(maxBits)
+ for level < 16 {
+ l := &levels[level]
+ if l.nextPairFreq == math.MaxInt32 && l.nextCharFreq == math.MaxInt32 {
+ // We've run out of both leafs and pairs.
+ // End all calculations for this level.
+ // To make sure we never come back to this level or any lower level,
+ // set nextPairFreq impossibly large.
+ l.needed = 0
+ levels[level+1].nextPairFreq = math.MaxInt32
+ level++
+ continue
+ }
+
+ prevFreq := l.lastFreq
+ if l.nextCharFreq < l.nextPairFreq {
+ // The next item on this row is a leaf node.
+ n := leafCounts[level][level] + 1
+ l.lastFreq = l.nextCharFreq
+ // Lower leafCounts are the same of the previous node.
+ leafCounts[level][level] = n
+ e := list[n]
+ if e.literal < math.MaxUint16 {
+ l.nextCharFreq = int32(e.freq)
+ } else {
+ l.nextCharFreq = math.MaxInt32
+ }
+ } else {
+ // The next item on this row is a pair from the previous row.
+ // nextPairFreq isn't valid until we generate two
+ // more values in the level below
+ l.lastFreq = l.nextPairFreq
+ // Take leaf counts from the lower level, except counts[level] remains the same.
+ if true {
+ save := leafCounts[level][level]
+ leafCounts[level] = leafCounts[level-1]
+ leafCounts[level][level] = save
+ } else {
+ copy(leafCounts[level][:level], leafCounts[level-1][:level])
+ }
+ levels[l.level-1].needed = 2
+ }
+
+ if l.needed--; l.needed == 0 {
+ // We've done everything we need to do for this level.
+ // Continue calculating one level up. Fill in nextPairFreq
+ // of that level with the sum of the two nodes we've just calculated on
+ // this level.
+ if l.level == maxBits {
+ // All done!
+ break
+ }
+ levels[l.level+1].nextPairFreq = prevFreq + l.lastFreq
+ level++
+ } else {
+ // If we stole from below, move down temporarily to replenish it.
+ for levels[level-1].needed > 0 {
+ level--
+ }
+ }
+ }
+
+ // Somethings is wrong if at the end, the top level is null or hasn't used
+ // all of the leaves.
+ if leafCounts[maxBits][maxBits] != n {
+ panic("leafCounts[maxBits][maxBits] != n")
+ }
+
+ bitCount := h.bitCount[:maxBits+1]
+ bits := 1
+ counts := &leafCounts[maxBits]
+ for level := maxBits; level > 0; level-- {
+ // chain.leafCount gives the number of literals requiring at least "bits"
+ // bits to encode.
+ bitCount[bits] = counts[level] - counts[level-1]
+ bits++
+ }
+ return bitCount
+}
+
+// Look at the leaves and assign them a bit count and an encoding as specified
+// in RFC 1951 3.2.2
+func (h *huffmanEncoder) assignEncodingAndSize(bitCount []int32, list []literalNode) {
+ code := uint16(0)
+ for n, bits := range bitCount {
+ code <<= 1
+ if n == 0 || bits == 0 {
+ continue
+ }
+ // The literals list[len(list)-bits] .. list[len(list)-bits]
+ // are encoded using "bits" bits, and get the values
+ // code, code + 1, .... The code values are
+ // assigned in literal order (not frequency order).
+ chunk := list[len(list)-int(bits):]
+
+ sortByLiteral(chunk)
+ for _, node := range chunk {
+ h.codes[node.literal] = newhcode(reverseBits(code, uint8(n)), uint8(n))
+ code++
+ }
+ list = list[0 : len(list)-int(bits)]
+ }
+}
+
+// Update this Huffman Code object to be the minimum code for the specified frequency count.
+//
+// freq An array of frequencies, in which frequency[i] gives the frequency of literal i.
+// maxBits The maximum number of bits to use for any literal.
+func (h *huffmanEncoder) generate(freq []uint16, maxBits int32) {
+ list := h.freqcache[:len(freq)+1]
+ codes := h.codes[:len(freq)]
+ // Number of non-zero literals
+ count := 0
+ // Set list to be the set of all non-zero literals and their frequencies
+ for i, f := range freq {
+ if f != 0 {
+ list[count] = literalNode{uint16(i), f}
+ count++
+ } else {
+ codes[i] = 0
+ }
+ }
+ list[count] = literalNode{}
+
+ list = list[:count]
+ if count <= 2 {
+ // Handle the small cases here, because they are awkward for the general case code. With
+ // two or fewer literals, everything has bit length 1.
+ for i, node := range list {
+ // "list" is in order of increasing literal value.
+ h.codes[node.literal].set(uint16(i), 1)
+ }
+ return
+ }
+ sortByFreq(list)
+
+ // Get the number of literals for each bit count
+ bitCount := h.bitCounts(list, maxBits)
+ // And do the assignment
+ h.assignEncodingAndSize(bitCount, list)
+}
+
+// atLeastOne clamps the result between 1 and 15.
+func atLeastOne(v float32) float32 {
+ if v < 1 {
+ return 1
+ }
+ if v > 15 {
+ return 15
+ }
+ return v
+}
+
+func histogram(b []byte, h []uint16) {
+ if true && len(b) >= 8<<10 {
+ // Split for bigger inputs
+ histogramSplit(b, h)
+ } else {
+ h = h[:256]
+ for _, t := range b {
+ h[t]++
+ }
+ }
+}
+
+func histogramSplit(b []byte, h []uint16) {
+ // Tested, and slightly faster than 2-way.
+ // Writing to separate arrays and combining is also slightly slower.
+ h = h[:256]
+ for len(b)&3 != 0 {
+ h[b[0]]++
+ b = b[1:]
+ }
+ n := len(b) / 4
+ x, y, z, w := b[:n], b[n:], b[n+n:], b[n+n+n:]
+ y, z, w = y[:len(x)], z[:len(x)], w[:len(x)]
+ for i, t := range x {
+ v0 := &h[t]
+ v1 := &h[y[i]]
+ v3 := &h[w[i]]
+ v2 := &h[z[i]]
+ *v0++
+ *v1++
+ *v2++
+ *v3++
+ }
+}